ON THE RECURSIVE SEQUENCE $x_{n+1}=\frac{x_{n-(5k+9)}}{1+x_{n-4}x_{n-9}...x_{n-(5k+4)}}$
Work
Year: 2008
Type: article
Abstract: In this paper a solution of the following difference equation$\ $was investigated \begin{equation*} x_{n+1}=\frac{x_{n-(5k+9)}}{1+x_{n-4}x_{n-9}...x_{n-(5k+4)}},\ n=0,1,2,... \end{equation*} where $x_... more
Source: Taiwanese Journal of Mathematics
Cites: 6
Cited by: 7
Related to: 10
FWCI: 0.639
Citation percentile (by year/subfield): 57.25
Subfield: Mathematical Physics
Field: Mathematics
Domain: Physical Sciences
Open Access status: bronze