Year: 2026
Type: preprint
Abstract: We prove that the Nieuwland number of the Octahedron is $3\sqrt{2}/4$. Along the way, we provide an elementary proof that Rupert's problem for the Octahedron admits no solution in which the outer projection is a hexagon.
Source: arXiv (Cornell University)
Authors: Steininger, Jakob, Yurkevich, Sergey
Institution: Statistics Austria
Language: English
Subfield: Discrete Mathematics and Combinatorics
Field: Mathematics
Domain: Physical Sciences
Open Access status: green
OpenAlex ID: W7212291386